The amount of oxygen needed for the burning of $4$ g of methane is:

4

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8

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16

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32

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Solution

The correct option is D $16$ g
The reaction is $C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$ .

$2$ moles of oxygen are needed for burning of $1$ mole of methane.

$4$ g of methane (molecular weight $= 16$ g/mol) corresponds to $0.25$ mol.

Thus, $0.5$ moles of oxygen are required for burning $0.25$ moles of methane.

The molecular weight of oxygen is $32$ g/mol.

Thus, $16$ g of oxygen are required for burning $4$ g of methane.

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The amount of oxygen needed for the burning of 4 g of methane is:

The amount of oxygen needed for the burning of $4$ g of methane is: