Question

The amount of sodium produced by the passage of 2 moles of electrons in the electrolysis of fused $NaCl$ is:

• A. 23 g
• B. 46 g
• C. 11.5 g
• D. 58.5 g

Answer 1

Answer: (B)

46 g

$N{a}^{+}+e^{-}\to Na$,
1 faraday of electricity deposits one gram equivalent of substance.
Acc. to above reaction, 23g (1 gram equivalent) of sodium is deposited with 1 faraday of electricity.
Thus, 46g of sodium is deposited with 2 faradays of electricity.