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Question

The amount of solutes ‘A’, ‘B’ and ‘C’ in 300g of water at 25°C,40°Cand 60°C in their saturated solutions are given below. Identify the correct statement from the following when hot saturated solutions of A, B and C are cooled slowly from 60°C to 25°C.

25°C40°C60°C
A110g90g105g
B140g170g180g
C130g150g140g

A

5g of A and 40g of B are precipitated.

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B

30g of B and 20g of C are precipitated.

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C

15g of A and g of C are precipitated.

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D

40g of B and 10g of C are precipitated.

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Solution

The correct option is D

40g of B and 10g of C are precipitated.


Explanation of correct option:

  • Let us assume the solutions are present in their saturated state at 60°C i.e., the amount present at 60°C for each of them.
  • For solute A

As temperature decreases form 60°C to 40°C, 15g of A will be precipitated. While going from 40°C to 25°C nothing will happen as the dissolved amount after precipitation ( 105-15=90g) is lower than the amount of saturated solution at 25°C (110g).

  • For solute B

As temperature decreases form 60°C to 40°C, 10g of B will be precipitated. While going from 40°C to 25°C another 30g will be precipitated. So, a total of 40g will be precipitated.

  • For solute C

As temperature decreases form 60°C to 40°C, nothing will happen as solubility increases. While going from 40°C to 25°C 10g of C will be precipitated.

So, a total of 15g, 40g, 10g of A, B and C respectively will be precipitated in each case.

40g of B and 10g of C are precipitated.

Hence, the correct option is (D).


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