The amount of sugar $(C_{12} H_{22} O_{11}$ ) required to prepare $2 L$ of its $0.1 M$ aqueous solution is:

68.4 g

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17.1 g

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34.2 g

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136.8 g

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Solution

The correct option is B $68.4 g$
$M o l a r i t y = \frac{(n)_{s o l u t e}}{V_{s o l u t e} (i n l i t r e)}$

$0.1 = \frac{A m o u n t o f s o l u t e}{342 \times 2}$

$A m o u n t o f s u g a r (C_{12} H_{22} O_{11}) = 68.4 g r a m$

Hence, option A is correct.

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The amount of sugar (C12H22O11) required to prepare 2L of its 0.1M aqueous solution is:

The correct option is B 68.4gMolarity=(n)soluteVsolute(inlitre)0.1=Amount of solute342×2Amount of sugar(C12H22O11)=68.4 gramHence, option A is correct.

The amount of sugar $(C_{12} H_{22} O_{11}$ ) required to prepare $2 L$ of its $0.1 M$ aqueous solution is:

The correct option is B $68.4 g$
$M o l a r i t y = \frac{(n)_{s o l u t e}}{V_{s o l u t e} (i n l i t r e)}$

$0.1 = \frac{A m o u n t o f s o l u t e}{342 \times 2}$

$A m o u n t o f s u g a r (C_{12} H_{22} O_{11}) = 68.4 g r a m$

Hence, option A is correct.