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Law of Mass Action

The amount of...

Question

The amount of sulphur present in $89.6$ litres of $S O_{2}$ gas is:

A

32

g

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B

64

g

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C

96

g

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D

128

g

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Solution

The correct option is D $128$ g
1 mole of gas occupies volume $= 22.4 L$
Number of moles in $89.6 L$ volume= $\frac{89.6}{22.4} = 4 m o l e s$
1 molecule of $S O_{2}$ has $1 m o l e$ atom of $S$ .
Therefore amount of sulphure present in $4 m o l e s$ of $S O_{2} = 4 \times 32 = 128 g$

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