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Depression in Freezing Point

The amount of...

Question

The amount of urea to be dissolved in $500 m l$ of water to produce a depression of $0.186 K$ in freezing point is :
Given :
$K_{f} = 1.86 K k g m o l^{- 1} ρ_{H_{2} O} = 1 g m L^{- 1}$

9 g

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6 g

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3 g

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18 g

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Solution

The correct option is C $3 g$
Since ,
$ρ_{H_{2} O} = 1 g / m L Weight of solvent = 500 g$
$Δ T_{f} = K_{f} \times m Δ T_{f} = K_{f} \times \frac{No of moles of urea}{weight of solvent (kg)} 0.186 = \frac{1.86 \times w \times 1000}{60 \times 500}$
$w = 3 g$

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