The amount of water produced by the combustion of $16 g$ of methane is:

16 g

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36 g

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18 g

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32 g

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Solution

The correct option is A $36 g$
$C H_{4} 1 mole + 2 O_{2} 2 mole ⟶ C O_{2} 1 mole + 2 H_{2} O 2 mole$

Mass of 1 mole methane is $16 g$ .

Since 1 mole of methane on combustion produces 2 moles of $H_{2} O$ .

Hence, $16 g$ of methane on combustion, produces $36 g$ of $H_{2} O$ .

Therefore, option $B$ is correct,

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Similar questions

Amount of water produced by the combustion of 16g of methane is:

Q. Calculate the amount of water (g) product by the combustion of

16 g

of methane.

Q. Amount of water produced by combustion of

3.2

g of methane in the presence of excess of oxygen is:

For the chemical equation given below, what is the amount of methane required to produce 72 g of water?
$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)$

Calculate the amount of water(g) produced by the combustion of 16 gram of Methane.

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The amount of water produced by the combustion of 16 g of methane is:

The correct option is A 36gCH41 mole+2O22 mole⟶CO21 mole+2H2O2 moleMass of 1 mole methane is 16g.Since 1 mole of methane on combustion produces 2 moles of H2O.Hence, 16g of methane on combustion, produces 36g of H2O.Therefore, option B is correct,

The amount of water produced by the combustion of $16 g$ of methane is: