Question

The amount of work done by $2$ mole of an ideal gas at $298$ K in reversible isothermal expansion from $10$ litre to $20$ litre is:

• A. $-120J$
• B. $-2452J$
• C. $-3434.6J$
• D. $2200J$

Answer 1

The correct option is C $-3434.6J$

Work done for the reversible isothermal process$=-$ $nRTln$ $\left(\frac{V_2}{V_1}\right)$

$=-2\times 8.314\times 298$ $ln\left(\frac{20}{10}\right)$

$=-3434.6J$

Option C is correct.