The amount of work done in moving 2.5 C charge over a potential difference 330 mV is:

1650 mJ

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132 mJ

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415 mJ

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825 mJ

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Solution

The correct option is D 825 mJ
Given,
Charge (q) = 2.5 C
Potential difference (V) = 330 mV

We know,
work done (W) = q x V
So, W = 2.5 C x 330 mV = 825 mJ (as 1 C x 1 mV = 1 mJ ).
Thus, the correct answer is option d.

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