The amount of work done is pumping water out of a cubical vessel of height 1 m is nearly (Given $ρ_{w a t e r} = 1000 k g / m^{3}$ )

5,000 J

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10,000 J

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5 J

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10 J

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Solution

The correct option is A 5,000 J
W.D to pump out water $= m g \frac{h}{2}$
$= 1000 \times 10 \times \times \frac{1}{2} = 5000 J$

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