Question

The amount of zinc required to produce $224$ ml of $H_2$ at NTP on treatment with dilute $H_{2}S{O}_4$ solution will be:

• A. $0.65$g
• B. $0.065$ g
• C. $65$g
• D. $6.5$g

Answer 1

Answer: (A)

$0.65$g

Let us consider the problem.

zinc reacts with sulfuric acid according to the following formula.

$Zn+H_{2}S{O}_4\to ZnS{O}_4+H_2$

Therefore, $1$ mole of zinc reacts to give $1$ mole of hydrogen

Volume of $1$ mole of hydrogen at $STP$ is $22400$ $ml$

$1$ mole of $Zn$ is $65$ grams

Therefore $0.65$ grams of zinc reacts to give $224$ $ml$ of hydrogen.

Hence, the correct option is $A$