The amplitude modulated current is given by $i = 125 [1 + 0.6 s i n 2900 t] s i n 10^{6} t$ . The depth of modulation is (in percent)

60

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6

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36

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66

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Solution

The correct option is B $60$
The current equation is given as $i = 125 [1 + 0.6 s i n 2900 t] s i n 10^{6} t$
Thus, we get $A_{c} = 125$ and $\frac{A_{m}}{A_{c}} = 0.6$
Thus, we get depth of modulation as $\frac{A_{m}}{A_{c}} \times 100 = 60 %$

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