wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The amplitude of a wave disturbance propagating in the positive x-direction is given by y=11+x2 at t = 0 and y=1[1+(xāˆ’1)2] at t = 2s. the wave speed is


A

1 m/s

No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B

1.5 m/s

No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C

0.5 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

2 m/s

No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is C

0.5 m/s


At t=2 sy=1[1+(x1)2]or xvt=x11=vt1=v×2v=0.5 m/s


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Building a Wave
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon