Question

The amplitude of a wave disturbance propagating in the positive x-direction is given by $y=\frac{1}{1+x^2}$ at t = 0 and $y=\frac{1}{[1+(x-1{)}^2]}$ at t = 2s. the wave speed is

• A. 1 m/s
• B. 1.5 m/s
• C. 0.5 m/s
• D. 2 m/s

Answer 1

The correct option is C

0.5 m/s

$Att=2sy=\frac{1}{[1+(x-1{)}^2]}orx-vt=x-1\Rightarrow 1=vt\Rightarrow 1=v\times 2\Rightarrow v=0.5m/s$