The amplitude of a wave disturbance propagating in the positive y-direction is given by- y - 11 - x2 at t - 0s and y - 11 - x - 12 at t - 2s- then wave velocity is

The correct option is C 0.5 m/s in 2 sec the wave moves 1 m ∴ Velocity = 12 m/s . ∴ Option C is correct. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Wave Equation

The amplitude...

Question

The amplitude of a wave disturbance propagating in the positive y-direction is given by:
$y = \frac{1}{1 + x^{2}}$ at $t = 0 s a n d y = \frac{1}{1 + (x - 1)^{2}}$ at $t = 2 s$ , then wave velocity is

1 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.5 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5 m / s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x -

y = \frac{1}{1 + x^{2}}

t = 0

y = \frac{1}{1 + (x - 1)^{2}}

t = 2 s

y = \frac{1}{1 + x^{2}}

t = 0

y = \frac{1}{1 + (x - 1)^{2}}

t = 2 s

x, y

y = \frac{1}{1 + x^{2}}

y = \frac{1}{1 + (x - 1)^{2}}

\frac{x}{2} m / s

y = \frac{1}{1 + x^{2}}

t = 0

y = \frac{1}{[1 + (x - 1)^{2}]}

t = 2 s

x

y

metres

X - d i r e c t i o n

y = \frac{1}{2 + x^{2}}

t = 0

y = \frac{1}{[2 + (x - 1)^{2}]}

t = 3 s

x

y

Join BYJU'S Learning Program