wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The amplitude of a wave represented by the displacement equation y=1asinωt±1bcosωt will be

A
a+bab
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a+bab
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a±bab
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a+bab
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D a+bab
Given ,
y=1asinωt±1bcosωt
We can re write the above equation as,
y=1asinωt±1bsin(π2+ωt)
This is a superposition of two waves, having phase difference ϕ=π2

Resultant amplitude
R=(A)2+(B)2+2ABcosϕ

R= (1a)2+(1b)2+2π1a×1bcos90
R=1a+1b=a+bab
Thus, option (d) is the correct answer.

flag
Suggest Corrections
thumbs-up
26
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon