CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The amplitude of electric field in a parallel light beam of intensity 4 Wm2 is :

A
35.5NC1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
45.5NC1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
49.5NC1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
54.8NC1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 35.5NC1
E0=2I0c= [2×4(8.85×1012×3×108)]=35.5N/C
Hence,
option (A) is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electromagnetic Spectrum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon