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Question

The amplitude of electric field in a parallel light beam of intensity 4 Wm2 is :

A
35.5NC1
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B
45.5NC1
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C
49.5NC1
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D
54.8NC1
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Solution

The correct option is A 35.5NC1
E0=2I0c= [2×4(8.85×1012×3×108)]=35.5N/C
Hence,
option (A) is correct answer.

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