The amplitude of 1i is equal to
0
π2
−π2
−π
Let z=1i⇒ z=1i×ii⇒ z=ii2 ⇒ z=−i
Since, z(0, -1) lies on the negative imaginary axis.
Therefore, arg (z) = −π2
∫π4−π4ex.sec2xdxe2x−1is equal to