Question

The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is $B_0$ = 510 nT. The amplitude of the electric field part of the wave is

• A. 120 N $C^{-1}$
• B. 163 N $C^{-1}$
• C. 510 N $C^{-1}$
• D. 153 N $C^{-1}$

Answer 1

The correct option is D 153 N $C^{-1}$

Given,

$B_0=510nT$

$c=3\times {10}^{8}m/s$

The magnitude of electric field is given by

$E_0=B_{0}c$

$E_0=510\times {10}^{-9}\times 3\times {10}^8$

$E_0=153N{C}^{-1}$

The correct option is D.