Question

If a projectile is fired with an initial velocity u at an angle θ from the horizontal, for what time does it remain in the air?

Solution

Vertical component of initial velocity, uy=u sinθ

At the highest point, vertical component of velocity will become zero.

From the first equation of motion, v=u+at⇒0=uy−gt⇒0=u sinθ−gt⇒t=usinθg

∴ Time of flight, T=2t=2u sin θg

At the highest point, vertical component of velocity will become zero.

From the first equation of motion, v=u+at⇒0=uy−gt⇒0=u sinθ−gt⇒t=usinθg

∴ Time of flight, T=2t=2u sin θg

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