The angle at which the circles $(x - 1)^{2} + y^{2} = 10 a n d x^{2} + (y - 2)^{2} = 5$ intersect is

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Solution

The correct option is B

$c o s θ = \frac{d^{2} - r_{1}^{2} - r_{2}^{2}}{2 r_{1} r_{2}}$

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Similar questions

(x - 1)^{2} + y^{2} = 10

x^{2} + (y - 2)^{2} = 5

The angle at which the circles $(x - 1)^{2} + y^{2} = 10 a n d x^{2} + (y - 2)^{2} = 5$ intersect is

The locus of the middle points of those chords of the circle $x^{2} + y^{2} = 4$ which subtend a right angle at the origin is

x^{2} + y^{2} + x + y = 0

x^{2} + y^{2} + x - y = 0

x^{2} + y^{2} + x + y = 0

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