The angle between a normal to the plane 2x-y+2z-1=0 and the z-axis is
cos-113
sin-123
cos-123
sin-113
sin-135
Explanation for the correct option(s)
Find the angle between a normal to the plane.
Consider the given Equation in vector form,
a→=2i→-j→+2k→b→=k→
We know that,
cosθ=a→.b→a⇀b→
Then,
cosθ=2i→-j→+2k→.k→2i→-j→+2k→k→cosθ=0+0+222-12+2212∵i.k=0,i.j=0,k.k=1cosθ=22-1+2cosθ=23θ=cos-123
Hence, the correct answer is Option C.