No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
π6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
tan−1(5√3)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
tan−1(5√3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ctan−1(5√3) x2+y2=1 -- (i) y=4√3x3 -- (ii)
On solving (i) and (ii) simultaneously we get, x2+48x6−1=0 ⟹(4x2−1)(12x4+3x2+1)=0 ⟹x2=14 ⟹ Points of intersection are (+12,+√32)
Slope of curve x2+y2=1at(12,√32)ism1=−1√3 Slope of curve y=3√3x3at(12,√32)ism2=3√3 ⇒Angle between two curves θ=tan−1∣∣
∣
∣
∣∣−1√3−3√31+(−3)∣∣
∣
∣
∣∣ =tan−1∣∣∣−10−2√3∣∣∣=tan−1∣∣∣5√3∣∣∣