Question

The angle between polariser and analyser is ${30}^{\circ }$ The ratio of intensity of incident light and transmitted by the analyser is

• A. 3:4
• B. 4:3
• C. $\sqrt{3}:2$
• D. $2:\sqrt{3}$

Answer 1

The correct option is A 3:4

Given,

$\theta ={30}^0$

By using malus law,

$I=I_{0}co{s}^2\theta$

$\frac{I}{I_0}=(cos30{)}^2$

$\frac{I}{I_0}=(\frac{\sqrt{3}}{2}{)}^2=\frac{3}{4}$

ratio, $I:I_0=3:4$

The correct option is A.