Question

The angle between the lines $\frac{x-2}{3}=\frac{y+1}{-2}=z-2$ and $\frac{x-1}{1}=\frac{2y+3}{3}=\frac{z+5}{2}$ is equal to:

Answer 1

The given lines are

$\frac{x-2}{3}=\frac{y+1}{-2}=\frac{z-2}{0}$

$\frac{x-1}{1}=\frac{y+\frac{3}{2}}{\frac{3}{2}}=\frac{z+5}{2}$

Now, angle b/w the lines

$cos\theta =|\frac{3+(-3)+0}{\sqrt{9+4}\sqrt{1+\frac{9}{4}+4}}|$

$cos\theta =0$

$\theta ={90}^o$