The angle between the lines $2 x = 3 y = - z a n d 6 x = - y = - 4 z$ is

\frac{π}{2}

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\frac{π}{6}

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\frac{π}{4}

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Solution

The correct option is A $\frac{π}{2}$
Angle between the lines $2 x = 3 y = - z, 6 x = - y = - 4 z$ is $90$
Since $a 1 a 2 + b 1 b 2 + c 1 c 2 = 0.$

where $a_{1} = \frac{1}{2}, a_{2} = \frac{1}{6}, b_{1} = \frac{1}{3}, b_{2} = - 1, c_{1} = - 1, c_{2} = \frac{- 1}{4}$
Thus the angle between them is $\frac{π}{2}$

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