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Question

The angle between the lines xcos30o+ysin30o=3
xcos60o+ysin60o=5 is

A
90o
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B
30o
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C
60o
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D
None of these
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Solution

The correct option is B 30o
xcos30+ysin30=3
y=xcot30+3cosec30
m1=cot30=3
xcos60+ysin60=5
y=xcot60+5cosec60
m2=cot60=1/3
tanθ=m1m21+m1m2
=∣ ∣3+1/31+(1/3)(1/3)∣ ∣
=∣ ∣3+13(1+1)∣ ∣=13
θ=30

1069943_1166827_ans_8865a91abee2462699f2dc5bcb2f1802.jpg

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