Question

The angle between the minute hand and the hour hand of a clock when the time is 4.20, is

• A. 0º
• B. 10º
• C. 5º
• D. 20º

Answer 1

The correct option is B

10º

Angle traced by hour hand in $\frac{13}{3}hrs={(\frac{360}{12}\times \frac{13}{3})}^{\circ }={130}^{\circ }$
Angle traced by min. hand in 20 min. $={(\frac{360}{60}\times 20)}^{\circ }={120}^{\circ }$
$\therefore$ Required angle $=(130-120{)}^{\circ }={10}^{\circ }$