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Area of Polygons

The angle bet...

Question

The angle between the pair of lines given by equation $x^{2} + 2 x y - y^{2} = 0$ is:

\frac{π}{3}

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\frac{π}{6}

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\frac{π}{2}

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0

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Solution

The correct option is D $\frac{π}{2}$
Given equation is $x^{2} + 2 x y - y^{2} = 0$
As we know lines are perpendicular if coeff. of $x^{2}$ and coeff. of $y^{2}$ adds to zero.
Here, $a + b = 1 - 1 = 0 .$
Hence, pair of lines are perpendicular.

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The angle between the lines represented by the equation $(x^{2} + y^{2}) s i n θ + 2 x y = 0$ is

Acute angle between the lines represented by $(x^{2} + y^{2}) \sqrt{3} = 4 x y$ is

x^{2} + 2 \sqrt{3} x y - y^{2} - 8 = 0

\frac{π}{6}

a

θ

(a, 0)

x^{2} + y^{2} = 1

\frac{π}{2} < θ < π

P

θ

(p .0)

x^{2} + y^{2} = 1

(\frac{π}{3}, π)

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