The angle between the pair of straight lines $x^{2} + 4 y^{2} - 7 x y = 0,$ is

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Solution

The correct option is C

$tan θ = \frac{2 \sqrt{h^{2} - a b}}{a + b}$
$θ = t a n^{- 1} \frac{2 \sqrt{\frac{49}{4} - 4}}{5} = t a n^{- 1} \frac{\sqrt{33}}{5}$ .

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The angle between the pair of straight lines $x^{2} + 4 y^{2} - 7 x y = 0,$ is

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The angle between the pair of straight lines x2+4y2−7xy=0, is

The correct option is C tanθ=2√h2−aba+b θ=tan−12√494−45=tan−1√335.

The angle between the pair of straight lines $x^{2} + 4 y^{2} - 7 x y = 0,$ is

The correct option is C

$tan θ = \frac{2 \sqrt{h^{2} - a b}}{a + b}$
$θ = t a n^{- 1} \frac{2 \sqrt{\frac{49}{4} - 4}}{5} = t a n^{- 1} \frac{\sqrt{33}}{5}$ .