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Question

The angle between the planes r.(2^i^j+2^k)=3 and r.(3^i6^j+2^k)=4

A
Cos1(1621)
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B
Sin1(421)
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C
Cos1(14)
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D
Cos1(34)
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Solution

The correct option is A Cos1(1621)
Let a=2^i^j=2^k,b=3^i6^j+2^k
If θ is the angle between the planes then
cosθ=cos(a,b)=ab|a||b|=6+6+44+1+49+36+4=163×7=1621

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