The angle between the straight lines x-1-2-y-2-5-x-3-4 and x-1-1-y-2-2-z-3-3 isA- 45-B- 30-C- 60-D- 90-

The correct option is D 900 cos θ=0 ⇒θ=90^0 ...

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Angle between Two Vectors

The angle bet...

Question

The angle between the straight lines

$\frac{x + 1}{2} = \frac{y - 2}{5} = \frac{x + 3}{4} a n d \frac{x - 1}{1} = \frac{y + 2}{2} = \frac{z - 3}{- 3} i s$

45⁰

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30⁰

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60⁰

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90⁰

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Solution

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\frac{x + 1}{2} = \frac{y - 2}{5} = \frac{z + 3}{4}

\frac{x - 1}{1} = \frac{y + 2}{2} = \frac{z - 3}{- 3}

\frac{x + 1}{2} = \frac{y - 2}{5} = \frac{z + 3}{4}

\frac{x - 1}{1} = \frac{y + 2}{2} = \frac{z - 3}{- 3}

\frac{x + 1}{2} = \frac{y - 2}{5} = \frac{z + 3}{4} and \frac{x - 1}{1} = \frac{y + 2}{2} = \frac{z - 3}{- 3}

2 x = 3 y = - z

6 x = - y = - 4 z

The angle between the lines $2 x - y + 3 = 0$ and $x + 2 y + 3 = 0$ is

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