The angle between the tangents drawn from the point 4- -2 to the ellipse 5 x 2-4 y 2-40-A- n-6B- n-4C- 3D- -2

The equation of the director circle of the given ellipse is x^2+y^2=18 The point (4,√(2)) lies on the director circle of the ellipse nbsp; 5x^2+4y^2=40. There ...

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Standard XII

Mathematics

Distance between Parallel Lines

The angle bet...

Question

The angle between the tangents drawn from the point $(4, \sqrt{2})$ to the ellipse $5 x^{2} + 4 y^{2} = 40.$

\frac{π}{6}

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\frac{π}{4}

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\frac{π}{3}

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\frac{π}{2}

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Solution

The correct option is D $\frac{π}{2}$
The equation of the director circle of the given ellipse is
$x^{2} + y^{2} = 18$
The point $(4, \sqrt{2})$ lies on the director circle of the ellipse $5 x^{2} + 4 y^{2} = 40.$
Therefore the angle between the tangents is $\frac{π}{2}$

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The angle between the tangents drawn from the point (4,√2) to the ellipse 5x2+4y2=40.

The correct option is D π2 The equation of the director circle of the given ellipse is x2+y2=18 The point (4,√2) lies on the director circle of the ellipse 5x2+4y2=40. Therefore the angle between the tangents is π2

The angle between the tangents drawn from the point $(4, \sqrt{2})$ to the ellipse $5 x^{2} + 4 y^{2} = 40.$

The correct option is D $\frac{π}{2}$
The equation of the director circle of the given ellipse is
$x^{2} + y^{2} = 18$
The point $(4, \sqrt{2})$ lies on the director circle of the ellipse $5 x^{2} + 4 y^{2} = 40.$
Therefore the angle between the tangents is $\frac{π}{2}$