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Question

The angle between the two vectors A=3^i+4^j+5^kandB=3^i+4^j5^k is :

A
60
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B
0
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C
90
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D
None of these
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Solution

The correct option is C 90
Angle is given as cosθ=A.B|A||B|
Thus, cosθ=(3^i+4^j+5^k).(3^i+4^j5^k)9+16+25=0

cosθ=0

Thus θ=900

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