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Question

The angle between the vectors (ˆi+ˆj) and (ˆj+ˆk) is

A
30°
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B
45°
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C
60°
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D
90°
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Solution

The correct option is C 60°
(ˆi+ˆj).(ˆj+ˆk)=0+0+1+0 =1cos θ=A.B(A−−(B|=12×2=12θ = 60°

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