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Byju's Answer
Standard XII
Physics
Vector Component
The angle bet...
Question
The angle between two asymptotes of the hyperbola
x
2
25
−
y
2
16
=
1
is
A
tan
−
1
4
5
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B
2
tan
−
1
4
5
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C
2
tan
−
1
5
4
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D
π
−
2
tan
−
1
4
5
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Solution
The correct option is
B
2
tan
−
1
4
5
We know that angle between asymptotes of hyperbola
x
2
a
2
−
y
2
b
2
=
1
is,
θ
=
2
tan
−
1
(
b
a
)
Here
a
=
5
and
b
=
4
Hence required angle is,
θ
=
2
tan
−
1
(
4
5
)
Suggest Corrections
0
Similar questions
Q.
Show that angle between the two asymptotes of a hyperbola
x
2
a
2
−
y
2
b
2
=
1
is
2
tan
−
2
b
a
(or)
2
sec
−
1
(
e
)
.
Q.
Evaluate:
(a)
sin
−
1
4
5
+
2
tan
−
1
1
3
=
π
2
(b)
tan
−
1
1
7
+
2
tan
−
1
1
3
=
π
4
(c)
tan
−
1
1
5
+
tan
−
1
1
7
+
tan
−
1
1
3
+
tan
−
1
1
8
=
π
4
Q.
The value of
sin
−
1
4
5
+
2
tan
−
1
1
3
=
Q.
I: The angle between the asymptotes of the hyperbola
x
2
−
3
y
2
=
3
is
30
0
II:The angle between the asymptotes of hyperbola
x
2
a
2
−
y
2
b
2
=
1
is
2
t
a
n
−
1
b
a
.
Which of the above statement is correct?
Q.
Prove that:
sin
−
1
(
4
5
)
+
2
tan
−
1
(
1
3
)
=
π
2
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