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Question

The angle made by two equal chords drawn from a point on the circle is bisected by the diameter through that point.


  1. False

  2. True 


Solution

The correct option is B

True 


Given, chord AB = chord AC.

As we know, if AD is the perpendicular bisector of the chord BC, then AD is a diameter.

(Perpendicular bisector of any chord passes through the centre)

In ABC, we have AB=AC, then the bisector of BAC is also perpendicular bisector of the side BC.

Since, AD is the perpendicular bisector of the chord BC, it passes through the centre of the circle.

Hence the bisector of BAC is a diameter.

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