The angle made by two equal chords drawn from a point on the circle is bisected by the diameter through that point.

True

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False

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Solution

The correct option is A
True

Given, chord AB = chord AC.

As we know, if AD is the perpendicular bisector of the chord BC, then AD is a diameter.

(Perpendicular bisector of any chord passes through the centre)

In $△ A B C$ , we have $A B = A C$ , then the bisector of $∠ B A C$ is also perpendicular bisector of the side BC.

Since, AD is the perpendicular bisector of the chord BC, it passes through the centre of the circle.

Hence the bisector of $∠ B A C$ is a diameter.

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