Question

The angle of a component is checked by using a 300 mm sine bar with gage blocks of 42.92 mm height under one end of the sine bar. The dial gage readings at each end of the work piece vary by 0.1 mm, the gage block end being high.
If this height is correct and also the upper roller is 0.5 mm bigger in diameter than lower roller, calculate the angle of the work piece

• A. $8^{\circ }{0}^{\prime }{47}^{\prime \prime }$
• B. $8^{\circ }{9}^{\prime }{28}^{\prime \prime }$
• C. $8^{\circ }{12}^{\prime }{21}^{\prime \prime }$
• D. $8^{\circ }{3}^{\prime }{40}^{\prime \prime }$

Answer 1

The correct option is B $8^{\circ }{9}^{\prime }{28}^{\prime \prime }$

42.32 + 0.25 = 42.57

$\sin \theta =\frac{42.57}{300}$

$\theta ={8.15}^{\circ }\approx 8^{\circ }{9}^{\prime }{28}^{\prime \prime }$