The angle of a cyclic quadrilateral ABCD are
<A=(2x+4)°,<B=(y+3)°, <c=(2y+10)°, <D=(4x-5)°.
Find x and y and hence values of four angles.

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Solution

since ABCD is a cyclic quadrilateral

angle A+angle C=180

therefore we get (x+y)=83

sum of all angles = 360

therefore we get (2x+y) = 116

thus

x=33 , y=50

angle D= 127

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The angle of a cyclic quadrilateral ABCD are <A=(2x+4)°,<B=(y+3)°, <c=(2y+10)°, <D=(4x-5)°. Find x and y and hence values of four angles.

since ABCD is a cyclic quadrilateral angle A+angle C=180 therefore we get (x+y)=83 sum of all angles = 360 therefore we get (2x+y) = 116 thus x=33 , y=50 angle D= 127

The angle of a cyclic quadrilateral ABCD are
<A=(2x+4)°,<B=(y+3)°, <c=(2y+10)°, <D=(4x-5)°.
Find x and y and hence values of four angles.

since ABCD is a cyclic quadrilateral

angle A+angle C=180

therefore we get (x+y)=83

sum of all angles = 360

therefore we get (2x+y) = 116

thus

x=33 , y=50

angle D= 127