Question

The angle of a triangle are $(2x+5{)}^{\circ }$, $(x+20{)}^{\circ }$ and $(2x+10{)}^{\circ }$. Find the value of '$x$'. Also, find the measure of each angle of the triangle.

Answer 1

The angles of the triangle are
$(2x+5),(x+20),(2x+10)$
Sum of all angles of a triangle $={360}^o$
Therefore, $2x+5+x+20+2x+10={180}^o$
$\Rightarrow 5x+35={180}^o$
$\Rightarrow x={29}^o$
Hence, angles of the triangle are ${63}^{\circ },{49}^{\circ },{68}^{\circ }$.