Question

The angle of a triangle are $(2x{)}^o,(3x+5{)}^o$ and $(4x-14{)}^o$. Then find the angles in degrees.

Answer 1

Sum of angles of a triangle is ${180}^o$

$\Rightarrow 2x+3x+5+4x-14={180}^o$

$\Rightarrow 9x={189}^o$

$\Rightarrow x={21}^o$

So the angles are

$2x=2\left(21\right)={42}^{o}3x+5=3\left(21\right)+5={68}^{o}4x-14=4\left(21\right)-14={70}^o$