Question

The angle of dip at a place is ${40.6}^{\circ }$ and the intensity of the vertical component of the earth's magnetic field $V=6\times {10}^{-5}Tesla$. The total intensity of the earth's magnetic field (l) at this place is

• A. $7\times {10}^{-5}Tesla$
• B. $6\times {10}^{-5}Tesla$
• C. $5\times {10}^{-5}Tesla$
• D. $9.2\times {10}^{-5}Tesla$

Answer 1

Answer: (D)

$9.2\times {10}^{-5}Tesla$

Given:-

The angle of dip at a place is ${40.6}^o$

intensity of the vertical component of the earth's magnetic field $V=6\times {10}^{-5}Tesla$

From the relation $B_v=Isin\varphi$

$I=\frac{V}{sin\varphi }=\frac{6\times {10}^{-5}}{sin{40.6}^0}=\frac{6\times {10}^{-5}}{0.65}=9.2\times {10}^{-5}tesla$