The angle of dip at a place is $60^{o}$ . At place the total intensity of earth's magnetic field is 0.64 units. The horizontal intensity of earth's magnetic field at this place is

1.28 units

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.64 units

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.16 units

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.32 units

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 0.32 units
The horizontal intensity of earth's magnetic field at this place is:
$B_{H} = B c o s ϕ = 0.64 \times c o s 60^{0} = 0.64 \times \frac{1}{2} = 0.32 u n i t s$

Suggest Corrections

Similar questions

The angle of the dip at a place is 40.6 $^{o}$ and the vertical component of the earths magnetic field $B_{V} = 6 \times 10^{- 5} T$ . The total intensity of the earth's magnetic field at this place is:

Q. The angle of dip at a place is

{40.6}^{\circ}

and the intensity of the vertical component of the earth's magnetic field

V = 6 \times 10^{- 5} T e s l a

. The total intensity of the earth's magnetic field (l) at this place is

At a place the angle of dip is $30^{o}$ . If the horizontal component of the earth's magnetic field is $H$ , then the total field intensity will be given by

Q. At a certain place, the horizontal component of the earth's magnetic field is

B_{o}

and the angle of dip is

45^{o}

. The total intensity of the field at that place will be

Q. At a certain place, the angle of dip is

60^{o}

and the horizontal component of earth's magnetic field

(B_{H})

0.8 \times 10^{- 4} T

. The earth's overall magnetic field is:

Join BYJU'S Learning Program

The angle of dip at a place is 60o. At place the total intensity of earth's magnetic field is 0.64 units. The horizontal intensity of earth's magnetic field at this place is

The correct option is D 0.32 unitsThe horizontal intensity of earth's magnetic field at this place is:BH=Bcosϕ=0.64×cos600=0.64×12=0.32units

The angle of dip at a place is $60^{o}$ . At place the total intensity of earth's magnetic field is 0.64 units. The horizontal intensity of earth's magnetic field at this place is

The correct option is D 0.32 units
The horizontal intensity of earth's magnetic field at this place is:
$B_{H} = B c o s ϕ = 0.64 \times c o s 60^{0} = 0.64 \times \frac{1}{2} = 0.32 u n i t s$