Question

The angle of elevation of a tower from a point on the same level as the foot of the tower is 30°. On advancing 150 metres towards the foot of the tower, the angle of elevation of the tower becomes 60°. Show that the height of the tower is 129.9 metres (Use $\sqrt{3}=1.732$)

Answer 1

Let h be height of tower and angle of elevation of foot of tower is 30°, on advancing
150 m towards the foot of tower then angle of elevation becomes 60°.

We assume that BC = x and CD = 150 m.

Now we have to prove height of tower is 129.9 m.

So we use trigonometrical ratios.

In a triangle,

Again in a triangle,

Hence the height of tower is m proved.