The angle of elevation of the top of a tower at a horizontal distance equal to the height of the tower from the base of the tower is
A
30∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
45∘
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
60∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
any acute angle
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B45∘ Let the angle of elevation be θ, from the same distance from pole as the length of the pole then tanθ=distancefrompolelengthofpole tanθ=1 tanθ=tan45 θ=45∘