Question

The angle of elevation of the top of a tower from a point A due south of the tower is ${30}^{\circ }$ and from B due east of the tower is ${60}^{\circ }$. If AB = 10, Find the height of the tower.

• A.
  
• B.
  
• C.
  
• D.
  

Answer 1

The correct option is A

$\angle OAP={30}^{\circ }and\angle OBP={60}^{\circ }$. Let OP=h
$tan{30}^{\circ }=\frac{h}{OA}$, since OAB is a right-angled triangle
So $h=\sqrt{10}\ast \sqrt{3}$