Question

The angle of elevation of the top of a tower from point at a distance of $100$ metres from its foot on a horizontal plane is found to be ${60}^{\circ }$. Find the height of the tower

• A. $173.2m$
• B. $196m$
• C. $144m$
• D. $123.2m$

Answer 1

The correct option is A $173.2m$

Let the height of the tower AC be h metres Given distance BC = 100 m, $\angle ABC={60}^{\circ }$
$\therefore \tan {60}^{\circ }=\frac{AC}{BC}=\frac{h}{100}\Rightarrow h=100\times \tan {60}^{\circ }=(100\times \sqrt{3})metre$
$=100\times 1.732=173.2m$