Question

The angle of incidence at which reflected light is completely plane polarized during reflection from air to glass (refractive index $\mu$) is,

• A. ${\sin }^{-1}\left(\mu \right)$
• B. ${\sin }^{-1}\left(1/\mu \right)$
• C. ${\tan }^{-1}\left(1/\mu \right)$
• D. ${\tan }^{-1}\left(\mu \right)$

Answer 1

The correct option is D ${\tan }^{-1}\left(\mu \right)$

During simultaneous reflection and refraction, from the surface of glass, the reflected light is completely plane polarized when angle of incidence is equal to the polarizing angle.

According to Brewster's law of polarization,
$\mu =\tan i_p,\text{where}{i}_p$ is polarizing angle of incidence

$\Rightarrow i_p={\tan }^{-1}\left(\mu \right)$

Hence, $\left(D\right)$ is the correct answer.