Question

The angle of incidence at which reflected light is totally polarised for reflection from air to glass (refractive index $n$) is :

• A. ${\sin }^{-1}\left(n\right)$
• B. ${\sin }^{-1}\left(1/n\right)$
• C. ${\tan }^{-1}\left(n\right)$
• D. ${\tan }^{-1}\left(1/n\right)$

Answer 1

Answer: (C)

${\tan }^{-1}\left(n\right)$

The refractive index of glass is n
If the light is incident on the surface with an angle of incidence i given by tan i $=\mu$ using the Brewster's law the reflected light is completely polarized.
Here tan i $=n$
i$=ta{n}^{-1}\left(n\right)$