Question

The angle of minimum deviation from a prism is ${37}^{\circ }.$ If the angle of prism is ${53}^{\circ },$ the refractive index of the material of the prism is

• A. 1.72
• B. 1.58
• C. 1.63
• D. 1.95

Answer 1

The correct option is B 1.58

$\mu =\frac{sin\frac{A+{\delta }_m}{2}}{sin\frac{A}{2}}=\frac{sin\frac{{53}^{\circ }+{37}^{\circ }}{2}}{sin\frac{{53}^{\circ }}{2}}=\frac{sin{45}^{\circ }}{sin{26.5}^{\circ }}$
= 1.58.